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What is the equation of the line that is parallel to the line y = x + 4 and passes through the point (6, 5)?

y = x + 3
y = x + 7
y = 3x – 13
y = 3x + 5

User Larjudge
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5.9k points

2 Answers

1 vote

Final answer:

The equation of the line parallel to y = x + 4 passing through the point (6, 5) is y = x - 1, which has the same slope as the given line but a different y-intercept, determined by the given point.

Step-by-step explanation:

The question asks for the equation of a line that is parallel to y = x + 4 and passes through the point (6, 5). Since the line we are looking for must be parallel, it will have the same slope as the given line, which in this case is 1 (since the coefficient of x is 1 in the given equation). The general form of the line we're looking for is y = x + b, where b is the y-intercept. To find the specific equation, we substitute the point (6, 5) into the equation to solve for b:

5 = (1)(6) + b
5 = 6 + b
b = 5 - 6
b = -1

Thus, the equation of the line that meets the conditions is y = x - 1, which is not represented in the options given. Since none of the options match, it's possible that there might have been a mistake in the options provided or an error in the transmission of the question. However, based on the information given, this is the correct equation for the line parallel to y = x + 4 that passes through (6, 5).

User Haventchecked
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5.7k points
2 votes

Answer:

b

Step-by-step explanation:

User AndreaBoc
by
6.3k points