Question

Ella's college professors assign homework independently from each other. ella knows that there is a 60% chance that she will have math homework tonight and a 70% chance that she will have english homework. what is the probability that she will not have math or english homework tonight? 10% 12% 42% 70%

Answer 1

To answer this question, you will multiply the chance of NOT having english homework (100-70=30% chance) by the chance of her NOT having math homework (100-60=40%).

This would be 0.3 x 0.4=0.12 or 12% chance of both occurring.

Answer 2

B. 12%

Explanation:

We have been given that Ella knows that there is a 60% chance that she will have math homework tonight and a 70% chance that she will have English homework.

Since we know that probability of not happening an event can be found by subtracting probability of happening the event from 1.

`\text{P(No math homework tonight)}=1-0.6=0.4`

`\text{P(No English homework tonight)}=1-0.7=0.3`

Since both events are independent so we will multiply probability of no math homework tonight by probability of no English homework to find no math or English homework tonight.

`\text{P(No math or English homework tonight)}=0.4* 0.3`

`\text{P(No math or English homework tonight)}=0.12`

Converting 0.12 to percent we will get,

`0.12* 100=12\%`

Therefore, the probability that Ella will not have math or English homework tonight is 12%.