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A 55.0-g piece of copper wire is heated, and the temperature of the wire changes from 19.0°C to 86.0°C. The amount of heat absorbed is 343 cal. What is the specific heat of copper? Show your work.

User Eman
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1 Answer

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Q = mc(ΔT)
Q = 343
m = 55
ΔT = 86 - 19 = 67

343 = 55(c)(67)
343 = 3685c
c = 0.0931 J/(g * C)
User Karan Singh Dhir
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