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Pat's Pizza made 21 cheese pizzas, 14 veggie pizzas, 23 pepperoni pizzas, and 14 sausage pizzas yesterday. Based on this data, what is a reasonable estimate of the probability that the next pizza made
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Pat's Pizza made 21 cheese pizzas, 14 veggie pizzas, 23 pepperoni pizzas, and 14 sausage pizzas yesterday.

Based on this data, what is a reasonable estimate of the probability that the next pizza made is not a cheese pizza?

User Tzar
by
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2 Answers

2 votes

Answer: 71%

Explanation:

User Hamed Minaee
by
8.9k points
3 votes
Not being cheese = P(not cheese) = 100 - P(cheese)
Being cheese is 21/the total

Total = 21 + 14 + 23 + 14
Total = 72

P(cheese) = 21/72 x 100
About 29%
P(not cheese) =71%
User Parrish
by
8.9k points
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