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Factor the expression. 21x^2 + 43x + 20 (7x – 5)(3x – 4) (7x + 5)(3x + 4) (7x – 5)(3x + 4) (7x + 5)(3x – 4)
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Factor the expression. 21x^2 + 43x + 20

(7x – 5)(3x – 4)

(7x + 5)(3x + 4)

(7x – 5)(3x + 4)

(7x + 5)(3x – 4)

User Kixoka
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2 Answers

6 votes
Hello,


21x^2 + 43x + 20\\ =21x^2+28x+15x+20\\ =7x(3x+4)+5(3x+4)\\ =(3x+4)(7x+5)\\ Answer B
User Terje Dahl
by
5.4k points
6 votes
Each choice has 7x and 3x which multiply to 21x^2.
The original trinomial has positive 20 and positive 43, so all factors of 21 and of 20 must be positive.
Only choice B has all positive terms, so choice B must be the answer.
User Nikasv
by
6.0k points
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