Question

HELP HELP ME ASAP!!!

At LEAST ONE value of x MUST be 7 (x = 7 or x = ?)

My teacher said that a, b, and c ALL have to be greater than 0 and b has to be greater than 1

At LEAST ONE extraneous solution

Answer 1

Part a

Let
`a=2`. Then, we have that

`7+2=√(7b+c)\\\\81=7b+c`

We can let
`b=11` and
`c=4`, meaning the equation is
`x+2=√(11x+4)`.

Part b

`x+2=√(11x+4)\\\\x^2 +4x+4=11x+4\\\\x^2 -7x=0\\\\x(x-7)=0\\ \\ x=0, 7`

Substituting both of these values into the equation, we see they are both solutions.

Part c

`x+10=√(10x+219)`