Question

Match the corresponding function formula with each function when h(x) = 3x + 2 and g(x) = 2 x .

1. k(x) = 2x + 3x + 2                   k(x) = g(x) ∘ h(x)

2. k(x) = 2x - 3x - 2                   k(x) = g(x) + h(x)

3. k(x) = (3x)2-x + 2-x + 1           k(x) = h(x) ÷ g(x)

4. k(x) = 23x + 2                            k(x) = g(x) - h(x)

5. k(x) = 2x(3x + 2)                     k(x) = g(x) × h(x)

6. k(x) = 3(2x) + 2                  k(x) = h(x) ∘ g(x)

Answer 1

To simplify the other user's answer (which is correct):

1 = B

2 = D

3 = C

4 = A

5 = E

6 = F

Alternatively, your right boxes should look like:

4

1

3

2

5

6

Answer 2

the correct functions are
h(x) = 3x + 2
g(x) = 2^x

I proceed to calculate the different values ​​of K (x)
case 1) k(x) = g(x) ∘ h(x)
g(x) ∘ h(x)=g(h(x))
k(x) = [2]^[3x + 2]-----------> is the option 4. k(x) = 2^(3x + 2 )

case 2) k(x) = g(x) + h(x)
k(x) = [2^x]+[3x + 2]=2^x+3x+2--------> is the option 1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)
k(x) = [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)
is the option 3.) k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)
k(x) = [2^x]-[3x + 2]=2^x-3x-2--------> is the option 2.) k(x) = 2^x - 3x - 2

case 5) k(x) = g(x) × h(x)
k(x) = [2^x]*[3x + 2]-----------> is the option 5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)
h(x) ∘ g(x)=h(g(x))
k(x)=3*[2^x]+2---------------> is the option 6. k(x) = 3(2^x) + 2