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a 3.5 kg book is sliding on a desk. The coefficient of kinetic friction between surfaces is 0.2.What is the size of the force of friction?

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The formula for the force of Kinetic friction is:

F_(k) =μ*N

Please consider μ as the coefficient of the kinetic friction = 0.2
N = Normal to the desk = m*g = 3.5 * 9.8 = 34.3 N

F_(k) = Force of Kinetic Friction = ?

Therefore,
The force of Kinetic Friction =
F_(k) = 0.2 * 34.3

F_(k) =6.86N

The size of force of Kinetic Friction = 6.86N.
User Dan Cantir
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