The first thing we need to do is factor the denominators in the rational expressions.
Notice that in the denominator of the first rational expression we have a common factor
![x](https://img.qammunity.org/2019/formulas/mathematics/college/lhtxftojjkzsmo3o2h4ilq8naohracejui.png)
, so we can factor x out:
![x^(2) +7x=x(x+7)](https://img.qammunity.org/2019/formulas/mathematics/college/f5osde9d2ln8jwpql41u1pqc0o4x0xx66p.png)
Now, the denominator of the second rational expression is a quadratic polynomial, we can factor it by finding tow numbers whose product will 21 and its sum will be 10. Those numbers are 7 and 3, (7x3=21 and 7+3=10):
![x^(2) +10x+21=(x+7)(x+3)](https://img.qammunity.org/2019/formulas/mathematics/college/abfch926dgbincc0g7vsrpc2rmrm6gq56d.png)
Lets rewrite our rational expression with our factored denominators:
![(6)/( x(x+7)) - (8)/((x+7)(x+3))](https://img.qammunity.org/2019/formulas/mathematics/college/ef2rm9p00a1cn0qrhuenmu11t4fn6lh3sf.png)
Now, to find the least common denominator we are going to take one of the common factors (x+7) and all the non-common factors: x and (x+3):
![x(x+7)(x+3)](https://img.qammunity.org/2019/formulas/mathematics/college/eu2r3adjakiixornjw7yzbkie11avsdo9f.png)
We can conclude that the correct answer is
a. x(x+7)(x+3)