Question

A 25 µF capacitor is connected to a 12-volt battery. How much energy can be stored in the capacitor? (1F = 106 µF)

Answer 1

w=1/2cvsqr....1/2*25*10^-6*144
0.0000125*144=0.0018=18micro farad

Answer 2

Energy stored in the capacitor is 0.0018 joules.

Step-by-step explanation:

It is given that,

Capacitance of the capacitor,
`C=25\ \mu F=25* 10^(-6)\ F`

Voltage of the battery, V = 12 volt

We have to find the energy stored in the capacitor. The energy stored inside the capacitor is given by :

`E=(1)/(2)CV^2`

`E=(1)/(2)* 25* 10^(-6)\ F* (12\ V)^2`

E = 0.0018 Joules

Hence, the energy stored in the capacitor is 0.0018 Joules.