Question

What volume of a 0.716 m kbr solution is needed to provide 30.5 g of kbr?

Answer 1

V_{solution}=0.355L

Step-by-step explanation:

Hello,

Potassium bromide moles are computed as:

`n_(KBr)=30.5gKBr*(1molKBr)/(119.9gKBr)=0.254gKBr`

Now, by recalling the molarity formula and solving for the volume, one obtains:

`M=(n_(KBr))/(V_(solution)) \\V_(solution)=(n_(KBr))/(M)\\V_(solution)=(0.254mol)/(0.716mol/L)\\ V_(solution)=0.355L`

Best regards.

Answer 2

Answer is: volume of KBr is 357 mL.
c(KBr) = 0,716 M = 0,716 mol/L.
m(KBr) = 30,5 g.
n(KBr) = m(KBr) ÷ M(KBr).
n(KBr) = 30,5 g ÷ 119 g/mol.
n(KBr) = 0,256 mol.
V(KBr) = n(KBr) ÷ c(KBr).
V(KBr) = 0,256 mol ÷ 0,716 mol/L.
V(KBr) = 0,357 L · 1000 mL/L = 357 mL.