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Helpppppppppppppppppppppppppppp

Helpppppppppppppppppppppppppppp-example-1
User Sandyiit
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2 Answers

4 votes
Nr B:
x = -7 +/- √(-64)
x = -7 +/- 8*√-1
x = -7 +/- 8i
User MMP
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5.9k points
2 votes
in this case it is to find the roots of the polynomial.
We have then:
x ^ 2 + 14x + 17 = -96
Rewriting:
x ^ 2 + 14x + 113 = 0
Applying resolver we have
x = (- b +/- root (b ^ 2 - 4ac)) / (2a)
Substituting values:
x = (- (14) +/- root ((14) ^ 2 - 4 (1) (113))) / (2 (1))
x = (- (14) +/- root ((196 - 452)) / (2 (1))
x = (- 14 +/- root (-256))) / (2)
x = (- 14 +/- i * 16)) / (2)
x = (- 7 +/- i * 8)
Answer:
x = (- 7 +/- i * 8)
(option 2)
User EBS
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