183,648 views
15 votes
15 votes
Which is NOT a solution for 5-2x ≥-3?
A 0
B 2
C 4
D 5

User Tomarto
by
2.9k points

2 Answers

30 votes
30 votes

Answer:

Answer D is correct

Explanation:

First, let us solve for x.


5 - 2x \geqslant - 3

First, subtract 5 by both sides.


- 2x \geqslant - 3 - 5 \\ - 2x \geqslant - 8

Divide both sides by -2.


x \leqslant 4

  • Remember that, when you divide or multiply both sides by a negative number it change the direction of the inequality sign.

Now, let us identify the equality sign and write the solutions of it.


\sf \leqslant \: \: \rightarrow \: \: x \: is \: less \: than \: or \: equals \: to \: 4

Solutions

x = { 4, 3, 2, 1, 0...}

Accordingly, as 5 is greater than 4, 5 is not a solution for this given inequality.

User Cosmin Onea
by
3.0k points
16 votes
16 votes

Answer:

D 5

Explanation:

Solve the inequality

5-2x ≥-3

Subtract 5 from each side

5-2x-5 ≥-3-5

-2x ≥-8

Divide by -2, remembering to flip the inequality

-2x/-2 ≤-8/-2

x ≤4

The only number not less than or equal to 4 in the choices is 5.

5 is not a solution

User Jonathan King
by
2.7k points