Question

Ga2O3(s) + 3SOCl2(l) --> 2GaCl3(s) +3SO2

In a certain reaction, 71.8 g of Ga2O3 is reacted with 110.8 g SOCl2.The GaCl3 produced is collected and its mass founded to be 97.66 g.
What is the theoretical yield of GaCl3?

Answer 1

The balanced equation is;
Ga2O3 + 3 SOCl2 → 2GaCl3 + 3SO2
the no. of moles of Ga2O3 = Weight / Molecular weight
= 71.8 / 187.44 = 0.383 moles >>> (1)
the no. of moles of SOCl2 = (Wt / M.wt) / 3 = (110.8/119)/3 = 0.310 moles >>> (2)
From (1) and (2),
∴ SOCl2 determines the yield of the reaction (lower no. of moles)
∴ No. of moles of GaCl3 = 0.310 * 2 = 0.620 moles >>> (3)
∴ the theoritical yield (weight in gram) of GaCl3 = no. of moles * M.wt.
= 0.620 * 176= 109.12 g