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A company has a cost equation of c=0.925x^2-4x+20 and a profit equation of p=-1.125x^2+6x+40. Solve for the breakeven point.
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Nov 9, 2019
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A company has a cost equation of c=0.925x^2-4x+20 and a profit equation of p=-1.125x^2+6x+40. Solve for the breakeven point.
Mathematics
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Tasos Vogiatzoglou
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0.925x^2 - 4x + 20 = -1.125x^2 + 6x + 40 (at break even point)
2.05x^2 - 10x - 20 = 0
x = [ - (-10) +/- sqrt(100 - 4*2.05*-20) / (2*2.05)
x = 6.40, -1.52 Ignore the negative
Answer is 6.40
David Torres
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Nov 13, 2019
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David Torres
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