Question

Resting body temperatures are normally distributed with an average of 98.25 degreesFahrenheit and a standard deviation of 0.73 degrees Fahrenheit. A nurse examines 40 patients in one hour. What is the probability the average temperature of the 40 patients is between 98.0 degrees Fahrenheit and 98.50 degrees Fahrenheit? (Round to the hundredths)A)0.97B)0.11542313C)0.99D)Sample size is not larger than 40 so we cannot compute probability

Answer 1

Resting body temperatures are normally distributed with an average of 98.25 degrees

Fahrenheit and a standard deviation of 0.73 degrees Fahrenheit. A nurse examines 40 patients in one hour. What is the probability the average temperature of the 40 patients is between 98.0 degrees Fahrenheit and 98.50 degrees Fahrenheit? (Round to the hundredths)



A)0.97

B)0.11542313

C)0.99

D)Sample size is not larger than 40 so we cannot compute probability

step 1

Find the z-scores

For x=98.0 degrees

z=(98-98.25)/0.73 --------> z=-0.3425

For x=98.50

z=(98.50-98.25)/0.73 ------> z=0.3425

using a Z-score Calculator

we have that

P=0.26803

step 2

we have that