Question

Please help me on my hw

Answer 1

We can find the x and y-intercept by substituting zero for x and y respectively.Part A

iven the eequation below;

`y=x+7`

When x=0

`\begin{gathered} y=0+7 \\ y=7 \end{gathered}`

when y=0

`\begin{gathered} 0=x+7 \\ x=-7 \end{gathered}`

Answer 1

`\begin{gathered} x-\text{intercept}=(-7,0) \\ y-\text{intercept}=(0,7) \end{gathered}`

Part B

`y=x^2-3`

When x=0

`\begin{gathered} y=0^2-3 \\ y=-3 \end{gathered}`

When y=0

`\begin{gathered} 0=x^2-3 \\ x^2=3 \\ x=\pm\sqrt[]{3} \\ x=-\sqrt[]{3}\text{ or x=}\sqrt[]{3} \end{gathered}`

Answer 2:

`\begin{gathered} x-\text{intercept}=(-\sqrt[]{3},0) \\ x-\text{intercept}=(\sqrt[]{3},0) \\ y-\text{intercept}=(0,-3) \end{gathered}`