V1 = old volume
V1 = pi*r^2*h
V1 = pi*3^2*7
V1 = 63pi
V2 = new volume (with radius doubled)
V2 = pi*r^2*h
V2 = pi*6^2*7
V2 = 252pi
Divide the two volumes
V2/V1 = 252pi/63pi = 252/63 = 4
Answer: 4
The larger volume is 4 times greater than the smaller volume.