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How many grams of iron, Fe, are reacted to form 16.0 grams of FeS (87.91 g/mol)

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the complete question and answer in the attached figure


How many grams of iron, Fe, are reacted to form 16.0 grams of FeS (87.91 g/mol)-example-1
How many grams of iron, Fe, are reacted to form 16.0 grams of FeS (87.91 g/mol)-example-2
User Oleg Kovalov
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Answer is: 10.164 grams of iron.

Balanced chemical reaction: 8Fe + S₈ → 8FeS.

m(FeS) = 16.0 g; mass of the compound.

M(FeS) = 87.91 g/mol; molar mass of the compound.

n(FeS) = m(FeS) ÷ M(FeS).

n(FeS) = 16 g ÷ 87.91 g/mol.

n(FeS) = 0.182 mol; amount of substance.

From chemical reaction: n(FeS) : n(Fe) = 8 : 8 (1 : 1).

n(Fe) = 0.182 mol.

m(Fe) = n(Fe) · M(Fe).

m(Fe) = 0.182 mol · 55.845 g/mol.

m(Fe) = 10.164 g.

User Shader
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