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Which equation best represents a trend line for the scatter plot?

y=−37x+4

y=73x+4

y=−73x+4

y=37x+4

Which equation best represents a trend line for the scatter plot? y=−37x+4 y=73x+4 y-example-1

2 Answers

1 vote

Answer:

Option A ic orrect.


y=-(3)/(7)x+ 4

Explanation:

Point slope form:

The equation of line is given by:


y-y_1=m(x-x_1) .....[1]

where m is the slope of line and a point
(x_1,y_1) lies on the line in the coordinate plane.

As per the statement:

You can see from the graph of line

We have two points i.e,

(0, 4) and (7, 1)

First calculate the slope:


\text{Slope} = (y_2-y_1)/(x_2-x_1)

then;


\text{Slope}(m) = (1-4)/(7-0) = -(3)/(7)

Now, substitute the value of m and (0,4) in [1] we have;


y-4=-(3)/(7)(x-0)

Simplify:


y-4=-(3)/(7)x

Add 4 to both sides we get;


y=-(3)/(7)x+ 4

Therefore, the equation best represents the trend line for the scatter plot is
y=-(3)/(7)x+ 4

User Uri Weg
by
6.4k points
3 votes
y = (-3/7)x + 4

Looking at the graph, you can see the trend line plotted. And conveniently, there are a couple of points on the trend line that are indicated. Those points being (0,4) and (7,1). The equation of a line in slope intercept form is:y = ax+b

Looking at the points available, the point (0,4) already gives us the y intercept since x is equal to 0. So our equation becomes:
y = ax + 4

Now we need to determine a which is the slope. The slope is the change in y divided by the change in x. So let's do that
(1-4)/(7-0) = -3/7

And now our equation becomes:
y = (-3/7)x + 4

And given formatting issues, the first option available is the correct one.
User EmmEff
by
5.7k points