Answer:
Angle K is 151°
Explanation:
Given :
JKLM is an isosceles trapezoid,
In which base angles ( either top or bottom ) are,
∠J=20x+9 and ∠M =14x+15,
In an isosceles triangle the angles on either side of the bases are the same measure,

⇒ 20x + 9 = 14x + 15
⇒ 20x - 14x = 15 - 9
⇒ 6x = 6
⇒ x = 1
Thus, the angles are,
⇒ ∠J = ∠M = 20 + 9 = 29°,
Let ∠K = ∠L = x,
By the property of quadrilateral,
∠J + ∠M + ∠K + ∠L = 360°
⇒ 29° + 29° + x + x = 360°
⇒ 58° + 2x = 360°
⇒ 2x = 302°
⇒ x = 151°
Hence, ∠K = 151°