Question

A tire at 21°C has a pressure of 0.82 atm. Its temperature decreases to –3.5°C. If there is no volume change in the tire, what is the pressure after the temperature change?

Use mc006-1.jpg.

0.75 atm
0.89 atm
1.1 atm
1.3 atm

Answer 1

0.75 atm. is the answer

Answer 2

Answer will be 0.75 atm .

According to gas law given by Gay lussac-

"pressure of a gas is directly proportional to the temperature(kelvins) of the gas when volume is kept constant".

`(P_1)/(T_1)=(P_2)/(T_2)`

given:

`P_(1)=0.82 atm`

`T_(1)=21^(\circ)C=21+273.15K=294.15K`

`P_(2)=?`

`T_(2)=-3.5^(\circ)C=-3.5+273.15K=269.65K`

Now putting the respective values is the equation (1)

`(P_1)/(T_1)=(P_2)/(T_2)`

`(0.82)/(294.15)=(P_2)/(269.65)`

`P_(2) = 0.75 atm`