Question

The Pythagorean theorem is a² + b² = c². Solve for b. b=±c+a−−−−√ b=±c2−a2−−−−−−√ b=±c2+a2−−−−−−√ b=±c−a−−−−√

Answer 1

B. b = +- sqrt (c^2 - a^2)

Explanation:

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Answer 2

`a^(2) +b^(2) =c^(2)`

As we have to solve for b, it means we have to isolate b

So first of all subtract
`a^(2)` from both sides

So we get

`b^(2) =c^(2) -a^(2)`

Now we need b , but its b^2 , so we can take square root on both sides.

taking square roots on both sides

`b= +- √(c^2 -a^2)`

Hence option B is correct