Question

Use a Pythagorean identity to rewrite the equation below using only the function sin θ. Then find the value of r if θ=30°,60°, and 90°.

r=4*sinθ*cos^2θ

Please explain/show steps, thanks!

Answer 1

`\bf sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\ -------------------------------\\\\ r=4sin(\theta )cos^2(\theta )\implies r=4sin(\theta )[1-sin^2(\theta )] \\\\\\ r=4sin(\theta )-4sin^3(\theta )\qquad \qquad \begin{cases} r=4sin(30^o)-4sin^3(30^o)\\ r=4sin(60^o)-4sin^3(60^o)\\ r=4sin(90^o)-4sin^3(90^o) \end{cases}`


`\bf \begin{cases} r=4\left( (1)/(2) \right)-4\left( (1)/(2) \right)^3\\\\ r=4\left( (√(3))/(2) \right)-4\left( (√(3))/(2) \right)^3\\\\ r=4(1)-4(1)^3 \end{cases}\implies \begin{cases} r=2-(1)/(2)\\\\ r=2√(3)-(3√(3))/(2)\\\\ r=4-4 \end{cases}\implies \begin{cases} r=(1)/(2)\\\\ r=(√(3))/(2)\\\\ r=0 \end{cases}`