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What is the mass of 40.34 x 10^23 H2 molecules at stp?

2 Answers

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every mol=6.22*10^23 molecules and every mol of H2 Is 2 gram
40.34*10^23/6.22*10^23=6.48 or 6.5
6.5*2=13 gram
User Appsmatics
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3 votes

Answer: The mass of hydrogen gas for the given number of molecules is 13.4 g

Step-by-step explanation:

We are given:

Number of hydrogen gas molecules =
40.34* 10^(23)

At STP conditions:


6.022* 10^(23) number of molecules are contained in 1 mole of a gas.

So,
40.34* 10^(23) number of molecules will be contained in =
(1)/(6.022* 10^(23))* 40.34* 10^(23)=6.7mol of hydrogen gas.

To calculate the mass of hydrogen gas, we use the equation:


\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of hydrogen gas = 6.7 moles

Molar mass of hydrogen gas = 2 g/mol

Putting values in above equation, we get:


6.7mol=\frac{\text{Mass of hydrogen gas}}{2g/mol}\\\\\text{Mass of hydrogen gas}=13.4g

Hence, the mass of hydrogen gas for the given number of molecules is 13.4 g

User Viktors
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