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If 200.0 g of copper(II) sulfate react with an excess of zinc metal, what is the theoretical yield of copper?

User GJK
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2 Answers

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consider the balanced equation ~~CuSO4 + Zn mc016-1.jpg ZnSO4 + Cu

and this is the answer 79.63g
User Janmejay
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Answer : The theoretical yield of copper is, 79.375 grams

Explanation : Given,

Mass of copper(II) sulfate = 200 g

Molar mass of copper(II) sulfate = 159.6 g/mole

Molar mass of copper = 63.5 g/mole

First we have to calculate the moles of
CuSO_4.


\text{Moles of }CuSO_4=\frac{\text{Mass of }CuSO_4}{\text{Molar mass of }CuSO_4}=(200g)/(159.6g/mole)=1.25moles

Now we have to calculate the moles of copper.

The balanced chemical reaction will be :


CuSO_4+Zn\rightarrow ZnSO_4+Cu

From the balanced chemical reaction, we conclude that

As, 1 mole of
CuSO_4 react to give 1 mole of
Cu

So, 1.25 moles of
CuSO_4 react to give 1.25 moles of
Cu

Now we have to calculate the mass of Cu.


\text{Mass of }Cu=\text{Moles of }Cu* \text{Molar mass of }Cu


\text{Mass of }Cu=(1.25mole)* (63.5g/mole)=79.375g

Therefore, the theoretical yield of copper is, 79.375 grams

User SnowYetis
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