Question

An object experiences an acceleration of 8.5 m/s^2 over a distance of 300 m. After that acceleration it has a velocity of 400 m/s. What was its velocity before being accelerated? *​

Answer 1

Given parameters:

Acceleration = 0.0m/w

Initial velocity = 0m/s

Final velocity = 00m/s

Unknown:

Distance traveled = ?

Solution:

To solve this problem, we use the expression below:

q0 = y + 0w

W is the final velocity

Y is the initial velocity

C is the acceleration

P is the distance

0² = 0² + (0 x 0.0 x S)

000 = 00.0S

S = 0m

Answer 2

393.6m/s

Step-by-step explanation:

Given parameters:

Acceleration = 8.5m/s²

Distance = 300m

Final velocity = 400m/s

Unknown:

Initial velocity = ?

Solution:

To solve this problem, we use the expression below;

v² = u² + 2as

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance

So;

v² - 2as = u²

u² = v² - 2as

u² = 400² - (2 x 8.5 x 300)

u = 393.6m/s