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In the diagram below, AB || CD, AD || BC, DEL CE, m/DCE = 30°

and m/ADE = 59°. Find m/ECB.
Answer: m/ECB
59°
=
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30°
attempt 6 out of 10

In the diagram below, AB || CD, AD || BC, DEL CE, m/DCE = 30° and m/ADE = 59°. Find-example-1
User Pallavi Tapkir
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1 Answer

4 votes
4 votes

Answer:

Angle EDC = 180 - 90 - 30 = 60° (sum of angles in triangle add up to 180°)

Angle ADC + angle DCB = 180° (interior angles, AB//CD)

59 + 60 + 30 + angle ECB = 180

Angle ECB = 180 - 59 - 60 - 30 = 31°