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Write the equation of the line that passes through the given point and is perpendicular to the given line.

(Only need 20 and 22)

Write the equation of the line that passes through the given point and is perpendicular-example-1
User David Rauca
by
3.1k points

1 Answer

12 votes
12 votes

Answer:

4x - 5y = 30

4x - 5(0) = 30

x1 = 7.5 y1 = 0

Find y-intercept

The y-intercept is where the graph crosses the y-axis. To find the y-intercept, we set x2=0 and then solve for y.

4x - 5y = 30

4(0) - 5y = 30

y2 = -6 x2 = 0

(x1,y1) and (x2,y2)

(7.5,0) and (0,-6)

Solve for x

To solve for x, we solve the equation so the variable x is by itself on the left side:

4x - 5y = 30

x = 1.25y + 7.5

Solve for y

To solve for y, we solve the equation so the variable y is by itself on the left side:

4x - 5y = 30

y = 0.8x - 6

User Adam Mendoza
by
2.3k points