Question

Please help thaank youu

What is the percentage of water in the hydrate CoCl2 • 6H2O? Show your work.

Answer 1

First, let's start off by finding the mass of this whole hydrate.
(Note: the unit of measurement for mass will be amu)

Let's find the molecular mass of each element.

`Co=58.933`

`Cl=35.45`

`H=1.008`

`O=15.999`

Now, let's find the mass of each compound.


`CoCl_2=58.933+2(35.45)=129.833`

`H_2O=2(1.008)+15.999=18.015`

We have 6 molecules of H2O, so multiply 18.015 by 6 then add that with the weight of CoCl2.


`6(18.015)=108.09`

`129.833+108.09=237.923`

Now divide 108.09 (mass of all the H2O in the hydrate) by 237.923 (total mass of hydrate).


`(108.09)/(237.923)`


`\approx0.45431`

Turn that into a percentage and you get 45.431%.
Hope this helps! :)