The empirical formula = the molecular formula = C₁₀H₂₀O
Further explanation
Given
m = 0.15 g menthol
V = 0.0337 L
T = 150 +273 = 423 K
P = 100.2 kPa =0.99 atm
Required
molar mass
The molecular formula
Solution
Ideal gas law :
PV=nRT
n=PV/RT
n=0.99 x 0.0337/0.082 x 423
n=9.6 x 10⁻⁴
n = mass/Molar mass
Molar mass = mass/n
Molar mass = 0.15/9.6 x 10⁻⁴
Molar mass = 156.25 g/mol
The empirical formula of Menthol : C₁₀H₂₀O
(The empirical formula)n= molecular formula
(C₁₀H₂₀O)n=156.25
(12.011.10+1,007.20+15,999)n=156.25
(156.25)n=156.25
n=1