Question

Using the formula V=Cl, find the voltage V in a circuit when the current C=3-j amps and the impedance l=3+2j ohms.

Algebra 2


Please help!

Answer 1

V = 11 +3j volts

Explanation:

You want the voltage in a circuit with current (3 -j) and impedance (3 +2j).

Voltage

The voltage is the product of current and impedance.

V = (3 -j)(3 +2j) = 3(3 +2j) -j(3 +2j)

= 9 +6j -3j -2j² = 9 -2(-1) +(6 -3)j

= 11 +3j

The voltage is V = 11 +3j.

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Additional comment

In electronics, the letter j is used in place of the letter i to mean √(-1). This is because i means something else. (Here, i is used for "impedance." It is conventionally used for "current.")

The multiplication is carried out as though the values were polynomials. In the end, j² is replaced by -1.

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