6. Find the equation for a parabola with vertex (5,-8) containing the point (1,1).

Shenme asked Aug 15, 2023

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Shenme asked Aug 15, 2023

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8 votes

Answer:

y=(9)/(16)(x-5)^2-8

Explanation:

The equation in vertex form is
y=a(x-5)^2-8 .

Substituting in the coordinates
(1,1) to solve for
,

$1=a(1-5)^2-8 \\ \\ 1=16a-8 \\ \\ 9=16a \\ \\ a=9/16$

So, the equation is
y=(9)/(16)(x-5)^2-8 .

Paqmo answered Aug 20, 2023

by Paqmo

3.1k points

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