Question

ABCD is a rhombus where m∠DAC=4x+9 and m∠DAB=11x−3

Answer 1

We are given

ABCD is a rhombus

so, firstly , we need to draw diagram

we can see that

diagonal bisects angle

so,

m∠DAB=2*m∠DAC

now, we can plug values

`11x-3=2(4x+9)`

now, we can solve for x

`11x-3=2*4x+2*9`

`11x-3=8x+18`

`11x-3+3=8x+18+3`

`11x=8x+21`

subtract both sides by 8x

`11x-8x=8x-8x+21`

`3x=21`

Divide both sides by 3

we get

`x=7`...............Answer