Question

A charge of 9.0 × 10–5 C is placed in an electric field with a strength of 4.0 × 104 . What is the electrical force acting on the charge?

Answer 1

The answer is 3.6 newtons.

Answer 2

3.6 N

Step-by-step explanation:

The electrical force acting on the charge is given by:

`F=qE`

where

q is the charge

E is the strength of the electric field

In this problem, we have

`q=9.0\cdot 10^(-5) C`

`E=4.0\cdot 10^4 N/C`

Substituting into the formula, we find the electrical force:

`F=(9.0\cdot 10^(-5) C)(4.0\cdot 10^4 N/C)=3.6 N`