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In the figure, QS = 15, RT = 36, and RT is tangent to radius QR with the point of tangency at R. Find QT.
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In the figure, QS = 15, RT = 36, and RT is tangent to radius QR with the point of tangency at R. Find QT.

In the figure, QS = 15, RT = 36, and RT is tangent to radius QR with the point of-example-1
User Augustine C
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the radius going through the tangent point is perpendicular to the tangent line, so ΔQRT is a right triangle.
QT²=QR²+RT²
QR and QS are both radii, so QR=QS=15
QT²=15²+36²
QT=39
User Konrad Jamrozik
by
6.3k points
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