Question

A 0.005 kg projectile has a velocity of 255 m/s to the right. What force is required to stop this projectile in 1.45 s?

Answer 1

F ≈ 0,879 N

Step-by-step explanation:

First, we calculate the value of the acceleration needed to stop the projectile.

That is:

V = V₀ + a.t

0 = 255 + a . (1,45)

a = - 255 / 1,45

a = -175,86 m/s²

Using the 2° Law of Newton:

∑F = m.a

F = m . a

F = 0,005 . (175,86)

F ≈ 0,879 N