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Write an algebraic rule to describe the translation C'(5, -4) -> C'(-2, 1) A. (x,y) -> (x - 2,y+ 1) B. (x,y) ->(x +7,y - 5) C. (x,y) ->(x -7,y + 5) D. (x,y) ->(x -3,y - 3)
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Write an algebraic rule to describe the translation C'(5, -4) -> C'(-2, 1)

A. (x,y) -> (x - 2,y+ 1)

B. (x,y) ->(x +7,y - 5)

C. (x,y) ->(x -7,y + 5)

D. (x,y) ->(x -3,y - 3)

User Alexander Klauer
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The answer is c. To get to (-2,1) from (5,-4), you have to add subtract 7 from 5 and add 5 to 1.
User Xavier KRESS
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