Question

The perimeter of a square JKLM is 48 units ..what is the x?

Answer 1

P=4*a, where P - perimeter, a - length of one side of the square.
if a=x+3 and P=48, then 4(x+3)=48;
x=9.
Answer: 9 units.

Answer 2

we know that

The perimeter of a square is equal to

`P=4b`

where

b is the length side of a square

In this problem we have

`b=(x+3)\ units\\P=48\ units`

substitute in the formula

`48=4(x+3)`

Solve for x

`12=(x+3)`

`x=12-3=9\ units`

therefore

the answer is

The value of x is
`9\ units`