Question

A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110.0 m.

Determine the acceleration of the car.

Answer 1

Answer: a = 8.10 m/s^2

Step-by-step explanation:

The car starts at rest, so:

V0= 0m/s

t= 5.21m/s

S = 110.0 m

Using one of the five uniformly accelerated motion formulas

S= V0t + 1/2 at^2

but V0 = 0 m/s

S = 1/2 at^2

a= 2S/ t^2

a = 2(110m)/ (5.21 s)^2

a = 8.10 m/s^2