Question

The first term of a geometric sequence is 3 and the multiplier, or ratio, is 2. What is the sum of the first 6 terms of the sequence?

A. 6
B. 9
C. 216
D. 189

Answer 1

I. 3*2^0
II. 3*2^1
III 3*2^2
IV. 3*2^3
V. 3*2^4
VI. 3*2^5
The sum 3*(2^0+2^1+2^2+2^3+2^4+2^5)=3*(2^6-1)=3*(64-1)=3*63=189
D is the answer