I drew the image that this problem gave me. Based on that image, I solved the required measurement using the sin theta formula:
sin θ = opposite / hypotenuse
On my drawing, I made an imaginary right triangle to solve for the distance.
Pls. see my attachment.
Sin θ = opposite / hypotenuse
Sin(30) = opposite / 48m
Sin (30) * 48m = opposite
24m = opposite
Sin(30) = opposite / 45 m
Sin(30) * 45 m = opposite
22.5 m = opposite
24m + 22.5m = 46.5 m
I am 46.5m away from my original starting point.