Question

As soon as possible please!

Answer 1

C).
`1 - sec^(2) A`

Explanation:

Lets say the bottom side is X, right side is Y, and hypotenuse is H.

`tan A = (Y)/(X)`

`tan B = (X)/(Y)`

`(tan A)/(tan B) = ((Y)/(X))/((X)/(Y)) = (Y)/(X) * (Y)/(X) = (Y^(2) )/(X^(2)) = ((Y)/(X))^(2) = tan^(2) A= 1 - sec^(2) A`