Register
What is the value of 81x2y3+z if x=3 y=4 and z=19
125k views
1 vote
What is the value of 81x2y3+z if x=3 y=4 and z=19

User Joepro
by
5.2k points

1 Answer

2 votes
Ok first of all I am assuming you mean

81.(x**2).(y**3) +z = Value

We just need to simply substitute x , y and z

81.(3*3)(4*4*4) +19 = Value

46656 + 19 = Value..............>> Value = 46675

User Deacon
by
5.9k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

6.0m questions

7.8m answers

Other Questions

Solve for y in terms of x. 2/3y - 4 = x y = x + 6 y = -x + 4 y = -x + 6 y = x + 4
Aliyah has $24 to spend on seven pencils. After buying them she had $10. How much did each pencil cost?
Ten gallons of paint were poured into two containers of different sizes. Use one variable to express the amount poured into each container
Use the normal model ​n(11371137​,9696​) for the weights of steers. ​a) what weight represents the 3737thth ​percentile? ​b) what weight represents the 9999thth ​percentile? ​c) what's the iqr of the weights
Evaluate a + b when a = –16.2 and b = –11.4 A. –27.6 B. –4.8 C. 4.8 D. 27.6
Link Copied!