Final answer:
Using the Law of Conservation of Momentum, we calculate that Car A was going approximately 15.93 m/s when it collided with Car B, given that both cars stuck together and slid away at 9.1 m/s post-collision.
Step-by-step explanation:
To determine how fast Car A was going when it hit Car B, we'll use the Law of Conservation of Momentum. The total momentum of a system is conserved if no external forces act on it. Since Car B was waiting to make a left turn, its velocity was 0 m/s. After the collision, both cars moved together with a combined mass of 3500 kg (2000 kg + 1500 kg) at a velocity of 9.1 m/s.
The total momentum before the collision (p_initial) must equal the total momentum after the collision (p_final):
p_initial = p_final
The momentum of Car A before the collision is m_A * v_A, and the momentum of Car B is m_B * v_B (which is 0 since Car B is stationary). After the collision, the momentum is (m_A + m_B) * v_final.
Setting the initial and final momentum equal:
m_A * v_A + m_B * v_B = (m_A + m_B) * v_final
2000 kg * v_A + 0 = 3500 kg * 9.1 m/s
Therefore, v_A = (3500 kg * 9.1 m/s) / 2000 kg
v_A = 15.925 m/s
So, Car A was going approximately 15.93 m/s when it collided with Car B.