Question

Find the equation of a line that passes through the point (1,-3) and has a gradient of 3.

Leave your answer in the form
a
x
+
b
y
=
c
Where
a
,
b
and
c
are integers.

Answer 1

3x+1y=0

Explanation:

the equation of a straight line on a graph is y= mx+c
where m is the gradient and c is the y intercept.

we know that the line passes through (1,-3) and has a gradient of 3, therefore we can substitute these values into the equation.

-3 = 3*1 +c
3 = 3+c
c = 3-3 = 0
therefore the equation of this line is y = 3x+0

now we have to write this in the form ax+by=c

3x+1y=0