Question

Aqueous hydrochloric acid (HCI) will react with solid sodium hydroxide (NaOH) to produce aqueous sodium chloride (NaCl) and liquid water (H₂O).Suppose 1.46 g of hydrochloric acid is mixed with 2.9 g of sodium hydroxide. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to 3 significant digits.

PLEASE HELP SOLVE

Answer 1

The balanced chemical equation for this reaction is:

HCl + NaOH = NaCl + H2O

1.46 g of HCl is equal to 0.0400 moles of HCl. (1.46/36.458). (36.485 being the molar mass of HCl in grams/mole).

2.9 g of NaOH is equal to 0.0725 moles of NaOH. (2.9/39.997). (39.997 being the molar mass of NaOH in grams/mole).

- From the reaction we can infer that it takes one mole of HCl and one mole of NaOH to form one mole of water. Therefore the limiting reactant in this case will simply be the one that we have the least amount of. So HCl is the limiting reactant.

- As stated previously, it takes one mole of HCl to produce one mole of H2O so that would mean that 0.0400 moles of HCl would produce 0.0400 moles of H2O.

0.0400*18.01 (18.01 being the molar mass of water in grams/mole) will give you the grams of H2O produced in this reaction.

Answer: 0.720 grams of H2O