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Can someone explain how to find x in these trig problems plz?

Can someone explain how to find x in these trig problems plz?-example-1

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You can find the angle left by 180-101-50=29
Then using the sine law, which means
a/sinA=b/sinB=c/sinC
We have 23/sin50=x/sin29
x=23(sin29)/sin50
Using the calculator to find the answer
I’m just a little lazy to do it
User Louie
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