Question

Iron has a density of 7.87 g/cm3. How much does 1 cubic feet of iron weigh?

Answer 1

To determine the weight of 1 cubic foot of iron, we need to convert the density from g/cm³ to lb/ft³. The weight is approximately 0.284 pounds.

Step-by-step explanation:

To calculate how much 1 cubic foot of iron weighs, we need to convert the density of iron from grams per cubic centimeter (g/cm³) to pounds per cubic foot (lb/ft³).

First, we need to convert the density of iron from g/cm³ to kg/m³. Since 1 kg = 1000 g and 1 m = 100 cm, the conversion is:

7.86 g/cm³ ÷ 1000 g/kg = 0.00786 kg/cm³ × (100 cm/m)³ = 0.00786 kg/m³

Next, we need to convert kg/m³ to lb/ft³. Since 1 lb = 0.453592 kg and 1 ft = 30.48 cm, the conversion is:

0.00786 kg/m³ × (0.453592 kg/lb) ÷ (30.48 cm/ft)³ = 0.284 lb/ft³

Therefore, 1 cubic foot of iron weighs approximately 0.284 pounds.

Answer 2

The answer would be 222853.216 grams

One foot equal to 30.48 centimeter which means for cubic feet it will be:
(30.48cm/ft)^3= 28316.8 cm^3/ft^3
Then, the weight of the iron would be:
weight = volume * density
weight = 1 ft^3 * (28316.8 cm^3/ft^3) * 7.87 g/cm3= 222853.216 grams = 222.9 kg