Question

A student increases the temperature of a 300 cm^3 balloon from 30c to 60c. what will the new volume of the ballon be

Answer 1

This problem uses the ideal gas law, PV = nRT. T for temperature must be in Kelvin, so we add 273.15 to the Celsius temperatures. We are then changing T from 303.15 K to 333.15K. The ratio of the temperatures 333.15/303.15 ~= 1.1. So holding pressure constant, the new volume of the balloon will be approximately 10% larger, or 330cm^3.

Answer 2

From Charles law the volume of a fixed mass of gas is directly proportional to the absolute temperature when pressure is kept constant.
Volume α temperature, mathematically; k = V/T
Therefore, comparing two gases V1/T1 = V2/T2
V1 =300 cm³ T1= 30°C (30 +273= 303K) V2= ? T2= 60°C (60 +273= 333K)
Thus, 300/303 = V2/333
V2 = (300 × 333)/ 303
= 329.703 cm³
Hence the new volume will be 329.703 cm³